Ans 4
Mass of HCl = 200 mg
Moles of HCl = mass/molecular weight
= (200 mg) / (36.46 mg/mmol)
= 5.485 mmol x 1mol/1000mmol
= 5.485 x 10^-3 mol
Volume of solution = 1.00 L
Molarity = moles/Volume
= (5.485 x 10^-3 mol) / (1.00 L)
= 5.485 x 10^-3 M
Dissociation of HCl
HCl = H+ + Cl-
pH = - log [H+]
= - log (5.485 x 10^-3)
= 2.26
please solve 4 and 5 c) What is the molar concentration of potassium in this solution?...
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