Question

the diagram below. A person who is1.1 m tall throws a bell with a speed of 26 m/s at an angle of 12 degrees above the horlzontal, as shown h-1.1 m, v 26 m/s, 8-12 degrees Use the acceleration due to gravity as g 10 m/s What are the x and y components of the initial velocity? mys THes 0/2 Subit Anw What are the x and y components of the ball's velocity when it is at its maximum height?" m/s Sbt Aner Tries 0/2 What are the x and y components of the bal's velocity the instant before it hits the ground? ) m/s Submit Ansr THes 0/2 What is the ball's speed (the magnitude of the velocity) the instant before it hits the ground mys Submt Arewr Thes 0/2 What is the bime of fight: that is, the time taken for the ball to hit the ground after i has left the person's hand som Ar Tries 0/2 Post Discussion

Answer 1

Ans COSO Le cose using Ucoso Ground Ground 6 UR we have to remember one thing on that is in a projectile the horizontal component of velocity (recos.o) never Changes always remains the same through out the entire motion. Only vertical component changes due. 1 (osino) to gravity.

Aus (1) Given er 26 als o - 12 x component of initial velocity is given by - 5 e - ecoso - 26 cos 12 = 25. 43 m/s Y component of initial velocity is given. by - Wy= usin o = 26 sin 120 = 5.4 m/s n X and Y component of initial velocity is given by - (25. 93 m/s , s. 4 m/s) Aus]

Ans (2) At maximum height y component will be 0 and X component of velocity will be ecoso as X component will be same for all positions. & X and Y component of velocity at maximum (25.43 m/s, omis) [Ans?

same Aus (3) Due to symmetrey, velocity and both the X and Y components will be same at point (13 with point in Downward velocity at point ® will be o sino = 5.4 mls. Now – (13 is at a height a 1.1 in from @ (nitting point) u From wn_u²+ 2gh we get, - 02 - (5.4) + 2x10x1.1 - 02-51.16 Here initial velocity will be v- 7. 15 ms. 5.4 mis as we considered ③ as initial and as final point

. Velocity component in X and Y direction before hitting the geround is given by - (25.43 m/s, 3.15 iss) [Ans] Aus (4) The magnitude of relocity before it hits the ground is given by a = duces ) 2 + (11,2 -) p = d2s.43)2 + (7-152 m/s. - TR = 26.42 m/s [Aus]
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