Question 19 The position of a simple harmonic oscillator is given by x(t)=(3.5m)cos(7.73nt) wheret is in...

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Answer 1

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solution o X(t) = 3.5m C6867.73 TAI maximum Ndocity (W) = a.w = 3.5X 7.73 V = 27.055 m/s 0 X(t) = 3.560867.7374) V = dyrn 3.5

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