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Suppose that is a continuous distribution with the following p.d.ffx) = 16x for Osx4 and value of EXO the Calculating the Exp
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Answer #1

Solution: Here we have to given that E(Xi ) = 1 and E(Xi2) = 2 now we have to find

E(X12 ( X2 - 5X1 )^2 )

but we know that

E(X12 ( X2 - 5X1 )^2 ) = E(X12 ( X22 +25X12 - 10 * X1 * X2 ))

E(X12 ( X2 - 5X1 )^2 ) = E(X12 * X22 +25X12 *X12 - 10 * X1 * X2 * X12 )

=[ E(X12 )* E( X22 ) ] + [ 25 * E(X12 ) * E( X12 ) ] - [ 10 *E( X1 ) *E( X2 ) * E ( X12 ) ]

because all the variable are independant

therefore

E(X12 ( X2 - 5X1 )^2 ) = [ 2 * 2] + [ 25 * 2 * 2 ] - [ 10 * 1 * 1 * 2 ]

Ans:

E(X12 ( X2 - 5X1 )^2 ) = 380

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