Question

0.335 Liters 0.00450 moles CuSO4 | Liter 2. What type of glassware would you use to prepare the solution in problem 1? 3. How many moles are there for 13.45 g of Kl? K= 39.10 I = 126.90 = 166 13.459 of KI Imole KI 0.081 moles of KI Telegrams 4. If one dissolved 13.45 g of Kl in solution with a final volume of exactly 125 ml, what is the concentration of that solution? 0.081 molcs KI 1 mole 5. How many moles of iron(III) chloride (FeCl3) are present in exactly 350 ml of an aqueous 0.000455 M solution of this solute? many milliters of solution would you need take from a container of a 0.115 M Becial solution in order to place exactly 0.0067 moles of ironfill) chloride into a beaker on your benchtop? How many moles of FeCl3 are there in 250 ml of a 5,6% w/w solution CHEMISTRY FACULTY SUNY COBLESKILL Fall 2019

Please help for questions 5-7

Answer 1

the questions 5 to 7 can be solved by using the formula of molarity

no.ofmolesof solute molarity = 2 volumeof solninliters

Q5, No. of moles of Felly = ? given: volume of solution - 350 ml = 0.350L Molarity of solution = 0.000455 M. Molarity = no.of moles of solute - volume of soin in litres 0.000455 = no. of moles 0.350 * no. of moles - 0.000455 X0.350 no.a moles = 1.5925x109 ano Q6+ given : To place 0.0067 moles of fell in beaker 0.0067 moles q felly means (0.0067 x 162.2) g of feliz (poamoles x molor mas (no gmotes of feels no = 1.08674g of feels milimétie q con needed - vol.q solution molarily = no qmoles : given mass moler mass vol.o son not of son volume of soln = 1.08 674 given mass 4 molan mas x mo 162-2 X 0.115 = 0.0582608 L TV : 58.26 m2 Any Q7 No. of moles 1 of Fella = ? vol. = 250mL means 5.69 of fell in loome of voln 100 w/w = 5.6% → 100 mL contains 5.69 g feliz 250 ML contains 5.6X250 g g fells = 14g of Feelz given mais = 14g molor mass - 162.291 mol no. of moles = giver mass = 14 = 0.0863 moles Ans. molor mass 162.2