Question

At a wild west show, a marksman fires a bullet at a 12g coin that's thrown straight up into the air. the marksman points his rifle at a 45 degree angle above the ground, then fires a 15g bullet at a speed of 550 m/s. just as the coin reaches its highest point, the bullet hits it and glances off, giving the coin an exactly vertical velocity of 120m/s at what angle measured with respect to the horizontal does the bullet ricochet away from this collision?

Answer 1

The initial momentum of the system is, p-0.01 5(550cos 4501 +550 sin 450)+12(0) At highest point velocity of the coin is zero p 5.83i +5.83j The final momentum of the system is, Pr -00 15(vcosôi + rsinaj)-0.012(120j) 0.0151, cosOi-(0.015v sin θ +1.44) According to conservation of momentum, 0.0 151, cos i-(0.0151, sin +1.44)j 5.83i+5.89 Compare horizontal coefficients on both sides, 0.015v cos 5.83 v cos e 388.6 Compare vertical coefficients on both sides, 0.015v sin 6 +1.445.83 v sin θ-292.6 Dividing above two equation to obtain the value of θ vsin θ 292.6 1, cos θ 388.6 tan θ-0.752 θ-tan-1 (0.752) e-370