Question

Prob #la(6 pts) A Regulator has a power dissipation of 10 watts is connected to a Heat sink with a thermal resistance of 3°0/w. If the case to function Resistance IS 5°c/w and the ambient temperature is 25°c, what is the function temperature? (Assume perfect contact between the Heatsink and the Regulator), Prob #16( 8 pts) For the following crevit, plot vout versus Vin, find Vmark and Unin. Also give the slope of Votiin. R2=2k 1K2 Vro R2=1.Ok2 - 0,= 5v Zener Da= 8v zenier Ra=2.0kr voltage forward Biased =0.6v) (for word Blased = 0.65) voltage

Answer 1

CAM power : low ..P Giben. dissipated case to junction resistance Else to sink resistance junctim Ojca soc/w Ocs : 3 clue junction temperature - Tjal Ambient Ambient temperature - TA-256 pe Tj - TA - je toest osa assume A-0 P = 10: Tj - 25 5 + 3 Tj.25. 2x10 Tjaloste problem (1-1) or the Griben V2, =sure ve for zeher 122=80) Voro.6 = Vg2 for forward sias

limit the circuit which It is a voltage limitor output voltage for win positive, output voltage will be negative . Because the input voltage at inverting terminal of op - 4те. The current flow through R, and to flow current Dg should be in forward bias and D, in reverse bius so voa -(Voat V2,] Vo = -10.6+5) --506 for reverse bias zener diode have voltage equal to its V₂. for vin 2o. No, will be positive. them D, will be forward bias and voltage across diode: 0.6 and diode or will be in reverse bias and voltage across diode Da = V22 [Work as a gener] :: Vos [ VD, + V287 - (0.6+8) -- 8.6 V

sin (VD, TV 22) - (VDqtv21) &-5-60 by ware form we plot Vo versus vin plot rc uinzo, Voa-(VD at V₂ = -5.6 Hotel ein co, vou (vo, Vra! a) 8.6V

a Vout 86 V Vai tuza). . suin bin - (ve, tv.) FSO By see this diagram we cari say that I find) the slope too mano o Because it is a horizontal line. so max Voltage Umaa = 8.6 v and minimum voltage Umin=-5.ru