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Q3(B) Balance the following chemical equations. (i) H2SiBr2 + H2O H2Si404 + HBr (ii) HSil3 + H2O → Hj Si10015 + HI (iii) H3PO

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Answer #1

(i) 4 H2SiBr2 + 4H20 H8Si404 + 8 HBr Left Side H = 16 Si = 4 Br = 8 O = 4 Right Side H = 16 Si = 4 Br = 8 O = 4

Balance equation: (ii) 10 HSil3 + 15 H20 H10S110015 + 30 HI Product side Reactant side H = 40 Si = 10 | = 30 O = 15 H = 40 Si

Balance equation: (iii) H3PO4 + LiOH LiH2PO4 + H20 Reactant side H = 4 P = 1 Li = 1 0 = 5 Product side H = 4 P = 1 Li = 1 O =

Balance equation: (iv) C5H8O2 + 2 (KH) + 2 HCI C5H1202 + 2 KCI Reactant side C = 5 H = 12 O = 2 K= 2 CI = 2 Product side C =

(v) Al(OH)3 + CsOH → KAIO2 + H20 The given equation (reaction) is wrong: At the reactant side cesium (cesium hydroxide) prese

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