The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e− Cl(g)+e−→Cl−(g)...
The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e− Cl(g)+e−→Cl−(g) Cs+(g)+Cl−(g)→CsCl(s) Which of these steps absorb energy and which release energy?
Homework Answers
Cs(s)→Cs(g)
Changing from solid to gas will absorb energy
12Cl2(g)→Cl(g)
breaking bond will absorb energy
Cs(g)→Cs+(g)+e−
This is ionisation reaction. This will absorb energy
Cl(g)+e−→Cl−(g)
This will release energy.
Cs+(g)+Cl−(g)→CsCl(s)
Formation of bond releases energy
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The formation of CsCl from Cs(s) and Cl2(g) involves the
following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e−
Cl(g)+e−→Cl−(g)...
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The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)?Cs(g) 12Cl2(g)?Cl(g) Cs(g)?Cs+(g)+e? Cl(g)+e??Cl?(g) Cs+(g)+Cl?(g)?CsCl(s) Which of these steps absorb energy and which release energy?
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