delta Go = delta HO - T*delta So
= 50,000 J - 298 K * 100 J/K
= 20200 J
= 20.2 KJ
Now use:
delta Go = -R*T*ln Kc
20200 = -8.314*298*ln Kc
Kc = 2.88*10^-4
What's the answer and why? 4. For a reaction with a Ho = +50 kJ and...
For the following reaction CCl4 (g) → C(s) + 2 Cl2 (g) Ho = +95.7 KJ; So = +142.2 J/K 1) What is Go for this reaction at 25 C? 2) What is the equilibrium constant for this reaction at 100 C? I need help with number 2) why would you not recalculate delta G for the reaction because its at a different temperature than 25C?
A certain reaction has Ho = 79.70 kJ and So = -55.80 J/K.
(a) Is this reaction exothermic, endothermic or isothermic
(neither)?
This reaction is ---Select--- exothermic endothermic
isothermic .
(b) Does this reaction lead to a decrease, an increase, or no
change in the degree of disorder in the system?
This reaction leads to ---Select--- a decrease an
increase no change in the disorder of the system.
(c) Calculate Go for this reaction at 298 K. If this
value is less...
The equilibrium constant of a reaction is 1.12e+02 at 312 K and 2.02e+03 at 431 K. Determine the following for this reaction: Ho= 11.37 Incorrect: Your answer is incorrect. kJ/mol So= J/mol-K What is the value of the equilibrium constant at 372 K? K=
The standard enthalpy of reaction (i.e. ΔH°) for a particular reaction is −20.1 kJ/mol. At 16.0 °C the equilibrium constant for the reaction is 2.30 × 103. Calculate the temperature (in °C) at which the equilibrium constant, K = 8.45 × 104. R = 8.314472 J⋅mol−1⋅K−1. Report your answer to THREE significant figures.
Part 1.)
A certain reaction has Ho = -26.10 kJ and So = 15.60 J/K.
(a) Is this reaction exothermic, endothermic or isothermic
(neither)?
This reaction is ---Select--- exothermic endothermic or
isothermic .
(b) Does this reaction lead to a decrease, an increase, or no
change in the degree of disorder in the system?
This reaction leads to ---Select--- a decrease, an
increase, or no change in the disorder of the system.
(c) Calculate Go for this reaction at 298 K. If...
question 22 For an equilibrium reaction, ΔG = 0 kJ at 327.0 K. If the standard enthalpy of this reaction is -46.9 kJ, and the standard entropy is 107.0 J/K, what is the equilibrium constant?
For the reaction N2(g) + O2(g)->2NO(g) AH° = 180.6 kJ and AS = 24.9 J/K The equilibrium constant for this reaction at 267.0 K is Assume that AHⓇ and ASº are independent of temperature.
1.) or the reaction Fe2O3(s) + 3H2(g)2Fe(s) + 3H2O(g) H° = 98.8 kJ and S° = 142.5 J/K The equilibrium constant for this reaction at 348.0 K is 2.) For the reaction C2H4(g) + H2O(g)CH3CH2OH(g) H° = -45.6 kJ and S° = -125.7 J/K The equilibrium constant for this reaction at 275.0 K is looking for the equilibrium constants
For the reaction 2802(g) + O2(g)—>2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at 298.0 K is Assume that AHⓇ and AS™ are independent of temperature.
1a) Consider the following reaction: 3 C(s) + 4 H2(g) → C3H8(g); ΔH° = –104.7 kJ; ΔS° = –287.4 J/K at 298 K What is the equilibrium constant at 298 K for this reaction? Report answer to TWO significant figures. 1b) Τhe enthalpy of vaporization of ammonia is 23.35 kJ/mol at its boiling point (–33 °C). Calculate the value of ΔSsurr when 1.00 mole of ammonia is vaporized at –33 °C and 1.00 atm. Report answer to THREE significant figures.