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Review Topics] Use the References to access important values if needed for this q uestion. Remember to use scientific notatio

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Answer #1

Given,

[H+] = 7.62 x 10-2 M

Autoionization constant of water, Kw = 10-14 at 25 oC

Now,

Kw = [H+][OH-] = 10-14

or, [OH-] = 10-14/(7.62 x 10-2)

                 = 1.31 x 10-13 M

Hence, the concentration of OH- = 1.31 x 10-13 M

---

Now, pOH = - log[OH-]

                 = - log(1.31 x 10-13)

                 = 12.9

Hence, the pOH of the solution = 12.9

---

pH = -log[H+]

or, pH = -log(7.62 x 10-2)

or, pH = 1.12

Hence, the pH of the solution = 1.12

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