Question

Could you explain how to Simplicate the circuit in Steady State after a long time?

What are the rules for reaching steady state and does it effect other resistors?

30 120V 50V 300 600 Problem 6 (15 points). After a very long time and after all the connections were made in the following circuit, calculate the voltage and power in the 400 resistance. 2H 1F 124 20e 2H -> 120 1200 1F 400 150 120V SA VAne: 100v Prne = 250W 3F Problem 7 (30 points). Calculate Vi in steady-state. 500 210,0mm 297.0mm X: 187 3mm Y: 107 4mm DROOKK.12146%

Answer 1

Answer: Given circuit is 122 2H 2o4 If trov 15 OSA 402 11ον 3F we know that at t o the capacitor acts as a open circuit & inductor acts as Short circuit due to a where for capacitor (let c) :- Capacitance (Impedance) ZTEC where f is frequency when t- - f do T. Xcoon open condition) out t oo where for Inductor (let 2) :- Inductance / 20 FL Impedance) whene too =) fo .. X -on ( short circuit non at tooo

i resulta below after Indector are circuit is taken capacitors are open short circuit in as shown circuit & 12r 120v © 20 ) 315r SA 3 Чо that implies 124 M . a 200 urt 120v (t @ SA uor voc by nodal analysis at ve we get v-120 -5 + 2040 20 V-120-5+ ČO 20 after sowing we get u= 150 volts Vox a Vuor - 15o = 100 volts Vuor = 100 volts too? Puor - 250 Watt you a uz R - HO

All description is in above papers.