Question

What is the pH of a 0.050 M HClO(aq) solution? K_a,HClO = 4.0 × 10⁻⁸ M.

Answer 1

for the aquaus solution, the equation is Hoc cao, Hale - H₂O ++ Och where, Ka = 4.0x16 PM and, Ka= [H30*3 [oCPI [HOc] Now, you know, the concentration is notice that every mole of HOCI dissociate produced one mole of CM30*and one mole of oce . it means that, if we take a, to be the Coneen tration of Hoce that ionizes, will prodreed a concentration of (+30+] and m, Comeentration of cores [H307) = a, CO CI] = x from the above equation ką = [»] [si] 0.050 Ka= 4.0x168 4.0x108- 22 0.050 u? = 4.0X108X 0.050 no 14.0x108xo oso n= 0.1x104, Since, r is sepessent [H3073 [H30+) = 0.1X104 M then, the pr of solution is defined as - pH = -log[H3Ot ] pH = -log[o.1X1643 PH - -