Question

The roots of the quadratic equation ax2 + bx + c = 0, a following formula: 0 are given by the In this formula, the term i2 - 4ac is called the discriminant. If b4ac 0 then the equation has a single (repeated) root. If -4ac > 0, th equation complex roots. Write a program that prompts the user to input the value of a (the coefficient of ), b (the coefficient of x), and c (the n has two real roots. If4aco, the equation has two t term) and outputs the type of roots of the equation. Further- more, if b0, the program should output the roots of the quadratic equation. (Hint: Use the function pow from the header file cmath to calculate the square root. tion pow is used.)

Answer 1

#include <iostream>
#include <cmath>//to use sqrt function
using namespace std;

int main()
{

float a, b, c, x1, x2, D, Real_Part, Imaginary_Part;
//declaration of variables
cout << "Enter coefficients a, b and c: ";

//cin is used to read the values of coefficients of the quardratic equation   
cin >> a >> b >> c;
// calculating Discriminant
D = b*b - 4*a*c;
  
  
if (D > 0)
// means roots exist and they are different
{
x1 = (-b + sqrt(D)) / (2*a);
x2 = (-b - sqrt(D)) / (2*a);
cout << "Roots are real and different." << endl;
cout << "x1 = " << x1 << endl;
cout << "x2 = " << x2 << endl;
}
  
//means roots exit and they are same   
else if (D == 0)
{
cout << "Roots are real and same." << endl;
x1 = (-b + sqrt(D)) / (2*a);
cout << "x1 = x2 =" << x1 << endl;
}
//if Discriminant is less than zero then roots will be Imaginary
else
{
Real_Part = -b/(2*a);
//to calculate imaginary part for each root
Imaginary_Part =sqrt(-D)/(2*a);
  
cout << "Roots are complex and different." << endl;
cout << "x1 = " << Real_Part << "+" << Imaginary_Part << "i" << endl;
cout << "x2 = " << Real_Part << "-" << Imaginary_Part << "i" << endl;
}

return 0;
}