Question

Two hockey pucks (ma-1.20 kg and mg = 1.40 kg) slide on a flat sheet of frictionless ice and then collide with each other. The diagram below shows a top-down view of the ice. Initially, hockey puck A moves in the *x direction with speed 4.80 m/s, while hockey puck B moves in the +x direction with speed 2.30 m/s. After the collision, hockey puck A moves off at an angle of 23.5' above the +x axis and hockey puck B moves off at an angle of 33.5' below the +x axis. Find the final speed of each puck, in units of m/s. before collision 23,5 A after collision 4.80 m/s B01 2.30 m/s

Answer 1

4.8mls 2.3 m/s - 1.40kg 02 33.50 3.50 - Total momentum along x-axis 4 y-axis will be constant. befose & Aften Collishion - let's Conserve first x-axis momentum - miUitma U2 = m. v, los dix mq Va las Or - (1620) X4.8 + 1-4X2-3 = (1-20) V, cos( 23.5) +(1.40) Va Cos (33.5) 8.98 = 1:1 V, + 1017 Va -0 - Conserve Y-axis momentum - o= mir, Sin23.5 - Mg Va fin 33-5° mi before After I 1.2 Sin 23.5% = 1.4 V2 Sin33.5) > 0.478V, = 0.772 Vq = v= 1.615 va - Put this vi value in ③ ean- 8.98 = (1+1)x(1.615) Va+ 1-1712 8.98= 2.946 V2 [va = 3.04 m/s I & Vi= 1.615V2 = 1.615 X3.04 T= 4.9096 m/s