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Question 2. Assume a host with global unicast address (2000:A45B:0ACD:1:1BA9:77FF:FE89:F7D1/128)16 Find: Link local address. Subnet ID....

Question 2.

Assume a host with global unicast address (2000:A45B:0ACD:1:1BA9:77FF:FE89:F7D1/128)16

Find:

  1. Link local address.
  2. Subnet ID.
  3. Physical (MAC) address of this host.

                                   

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Answer #1

1. Link Local Address: Link Local address in IPv6 is formed as 64-bit(FE80::) reserved + next 64-bit ( 64-bit MAC Address from IPv6). So, in above case Link Local Address will be FE80:0:0:0:77FF:FE89:F7D1

2. Subnet ID: It is the fourth (16 bit block) in IPv6 address. From the given IPv6 address 2000:A45B:0ACD:1:1BA9:77FF:FE89:F7D1. "1 is the subnet ID"

3. Physical (MAC Address): It is extracted from the last 64-bits of IPv6 address. If you look at the format. 48-bit MAC address is converted to last 64-bit IP address by dividing 48-bits into 24-bits and 24-bits. and inserting FFFE in between them. Apart from that, In IEEE format, we invert bit 7 to finally convert 48-bit into 64-bit. So, with this process, the MAC address will come as 19:A9:77:89:F7:D1

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