From the stoichiometry of the reaction
1 mol I2 produced from = 2 moles of NaI
253.81 g I2 produced from = 2*149.89 = 299.78 g of NaI
67.4 g I2 produced from = 299.78*67.4/253.81
= 79.61 g of NaI
php?id 4954882 TBOOK 17 of 24 How many grams of sodium iodide, Nal, must be used...
How many grams of sodium iodide must be used to produce 68.9 g iodine? STRATEGY 1. Convert the mass of 1, to moles. 2. Convert the number of moles of I, to the number of moles of Nal 3. Convert the number of moles of Nal to grams Step 1: Convert 68,9 g iodine, L2 - to moles. 68.9 g iodine = mol
2NaI + Cl2 = I2 + 2NaCl How many grams of sodium iodide, NaI, must be used to produce 38.7 grams of iodine, I2? Mass:__ Thank you!
1. According to the following reaction, how many grams of sodium iodide are required for the complete reaction of 32.5 grams of chlorine gas? chlorine (g) + sodium iodide (s) ---> sodium chloride (s) + iodine (s) 2. According to the following reaction, how many grams of carbon dioxide will be formed upon the complete reaction of 21.3 grams of oxygen gas with excess carbon monoxide? carbon monoxide (g) + oxygen (g) ----> carbon dioxide (g) 3. According to the...
Iodine is prepared both in the laboratory and
commercially by adding Cl, (g) to an aqueous solution containing
sodium iodide. 2 Nal(aq) + C1,(g) I, (s) + 2 NaCl(aq) How many
grams of sodium iodide. Nal, must be used to produce 91.4 g of
iodine. I2?
Iodine is prepared both in the laboratory and commercially by adding Cl, (g) to an aqueous solution containing sodium iodide. 2 Nal(aq) + Cl2(g) + 1 (s) + 2 NaCl(aq) How many grams of...
lodine is prepared both in the laboratory and commercially by adding Ch(9) to an aqueous solution containing sodium iodide: How many grams of sodium iodide, Nal, must be used to produce 47.5 g of iodine, 127 Number g Nal
The Wombustion of propane may be described by the chemical equation CH,(8) +5028) 300,(0) + 4H,0(8) How many grams of O2(%) are needed to completely burn 84.2 8C,H,()? mass 02:| . What is the maximum mass of S, that can be produced by combining 88.0 g of each reactant? 850, + 16H,$ 35, + 16H,0 mass of S: Iodine is prepared both in the laboratory and commercially by adding Cl, (g) to an aqueous solution containing sodium iodide. 2 Nal(aq)...
Assignment Score: 48% Resources Hint Check Answer Question 13 of 27 > lodine is prepared both in the laboratory and commercially by adding Cl(s) to an aqueous solution containing sodium iodide. 2 Nal(aq) + Cl, (g) 1,(s) + 2 NaCl(aq) How many grams of sodium iodide, Nal, must be used to produce 28.2 g of iodine, 1,7 mass: Nal Q MOC Published by
1.According to the following reaction, how many grams of hydrogen iodide will be formed upon the complete reaction of 21.0grams of iodine with excess hydrogen gas? hydrogen (g) + iodine (s)------->hydrogen iodide (g) __________________ grams hydrogen iodide. 2.According to the following reaction, how many grams of ammonium chloride are needed to form 24.2 grams of hydrochloric acid? ammonium chloride (aq) ------->ammonia (g) + hydrochloric acid (aq) ______________________grams ammonium chloride
Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide. 2NaI(aq)+Cl2(g)⟶I2(s)+2NaCl(aq) How many grams of sodium iodide must be used to produce 82.3 g iodine ?
How many grams of lead (II) iodide would be produced based on
the amount of lead (II) nitrate used?
What is the theoretical yield of lead (II) iodide (in grams) for
this reaction based on the limiting reactant?
What was the actual yield (in grams) of the solid for this
experiment?
What was the percent yield of the reaction?
How many moles of iodide were left unreacted?
How many moles of NaI were left unreacted?
How many grams...