Assume, number of lite beer keg as 'x' and the number of Dark beer keg as 'y'
Given that,
For one keg of lite beer, 2 minutes are required.
Hence, 'x' keg 2x minutes are required and for 'y' keg of Dark beer 4y minutes are required.
Total available time = 8 hours = 480 minutes.
Total time used for producing both types of beer: 2x + 4y
this must be less than total available time
So, time constraints:
2x + 4y ≤ 480
And for malt constraint:
5x + 3y ≤ 675
In order to maximize profit, the objective function: max 3x +
2y
solve:
2x + 4y ≤ 480 (time constraint)
5x + 3y ≤ 675 (malt constraint)
Solving: x = 90 keg of Lite beer
y = 75 keg of Dark beer
Profit = 420 per day
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