By application of the impulse-invariant transformation of H (s), the following transfer functions have been obtained. Find H (s), assuming T = 0.1 s:
H1(z) = 2z
(z − e−0.2)(z − e−0.1)
H2(z) = z − e−0.6
(z − e−0.5)(z − e−0.4)
H3(z) = z
(z − 0.9)(z − 0.3)
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By application of the impulse-invariant transformation of H (s), the following transfer functions have been obtained. Find H (s), assuming T = 0.1 s: H1(z) = 2z (z − e−0.2)(z − e−0.1) H2(z) = z − e−0.6 (z − e−0.5)(z − e−0.4) H3(z) = z (z − 0.9)(z − 0.3)
y1 = 0.6 811) 0.3 y2 =0.5 (1)=0.2 h1=0.4 812) = 0 h2=0.3 12) = 0 o Let the learning rate be 0.1, the old connection weight from y1 to hi is 1, what is the new weight? Ο Ο Let the learning rate be 0.1, the old connection weight from y1 to h1 is 1, what is the new weight? Ο Ο Ο 1.24 Ο 1.024 Ο 1.012 mint
The figure shows the behavior of Pt and Ag cathodes at which
reduction of H3O to H2(g) occurs. Explain why the two curves are
not superimposed.
Pt Ag 0.5㎂ -0.2-0.3-0.4-0.6-0.7-0.8-0.9 E(V vs. S.C.E.)
Pt Ag 0.5㎂ -0.2-0.3-0.4-0.6-0.7-0.8-0.9 E(V vs. S.C.E.)
E Volts) 6 co2/glucose 0.43] -0.5 I-0.42] -0.4 NAD /NADH 0.32] -03 -0.2 -0.1 Fumarate/succinate 0.03] 0.0 [0.10] +0.1 2 H /H2 I- 0.27] FADIFADH2 0.18] S°/H2S CoQ/CoQH2 +0.2 Cyt C (Fe )Cyt C (Fe+) [0.25] +0.3- +0.4 +0.5 +0.6 No,INO2 [0.421 Fe3+/Fe2+ 4 0,H20 (0.82108 10.77) +07
Create chart or table Consider the system with the impulse response ht)e u(t), as shown in Figure 3.2(a). This system's response to an input of x(t) 1) would be y(t) h(r ult 1). as shown in Figure 3.2(b). If the input signal is a sum of weighted, time-shifted impulses as described by (3.10), separated in time by Δ = 0.1 (s) so that xt)01-0.1k), as shown in Figure 3.2(c), then, according to (3.11), the output is This output signal is...