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online homework manager Course Messages Forums Calendar Gradebook Home > MAT115-7874-Summer 2020 > Assessment Homework#4-2: Parallel and Perpendicular lines Score: 0.6776 1/6 answered Question 2 Consider the equation -- 5x – 3y = - 9 A line parallel to the above line would have a slope of A line perpendicular to the above line would have a slope of Submit Question

Answer 1

Q.4 Souly like I passes through (-214) and (012) line 2: passes through (21-9) and (101-13) slope of line 1: M1 = 92-9, X-X MN 0 +2 mi- slope of line 2: M2= 92-9 -13+9 To-L ool's 8 m2---1 24 mi .M2 & 1 m, & m2 So line is neither parallel nor pearpendicular to lines. Q-J solun!- line 1: passes through (15, 14) and (916) passes through (81-4) and (2017) slop of line 1: -8 Mis 92-9) 6-14 9-15 X12-11 17ty my 3 slope of line & m2 = 49-9, X2-X maa - 2 1 - mi.m2 = (3):(-3)=-1, linel I perpendiculas to of

Q & solant slope of equation -ox-3y = -9 standard equation of line g = mx + c Here, Rewrite giver equation and compair with standard one m- slope w y= x + 3 3 slop (m) = -5 - Ansnes 3 0.3 school line : pass through (12-7) and (32-4) line 2: pass through (115) and (-2,-4) 22-24 mln slope of line 1, m, = 92-9 - - 4+1 3-12 mes- molle 3 slore of line 2, M₂ = 92-9, -4-5 = olm Xq-x, Mr = 3 m. m2 = Here, 1/3 x3 = -1 m. m2 = -1, so like Sa are perpendiclar to each