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4AHW9: Problem 15 Previous Problem Problem List Next Problem (1 point) Supppose A is an invertible n x n matrix and V is an e

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an eigen vector of A with associated j is eigenvalue 7. Therefore A J = 78 (1) (a) We have 2 A’ v = A(AV) = A(7) = 7(Av) = 7has an The matrix © (A-5 In ) = A ū - 5ū = 7% -5 J (using (1) → (A-5 In) ✓ = 2 This shows ù is an eigenvector of A A-5 In an

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