Question

5) Consider the circuit below. 2.0 ?F 4,0 ?F 3.0 uF 90 V (a) What is the charge on the 4.0-uF capacitor? (b) What is the charge on a 2.0-uF capacitor? (c) What is the charge on the 3.0-uF capacitor? (d) What is the potential difference across the 6.0-uF capacitor?

Answer 1

rightarrow let c_1 , C_2 , C_3 and C_4 are the capacitors connected as shown in figure. rightarrow Here, in the above circuit we can see that capacitors c_1 and C_2 are connected in series rightarrow so the equipment capacitance of C_1 and C_2 nill be: 1/c_12 = 1/C_1 + 1/C_2 Therefore 1/C_12 = 1/2 + 1/4 Therefore 1/C_12 = 2 + 1/4 Therefore 1/C_12 = 3/4 Therefore C_12 = 4/3 mu f similarly,in the given circuit we can see that capacitors C_3 and C_4 are connected in series rightarrow so the equivalent circuit diagram of above situation is as follows rightarrow Now, the equivalent capacitance of capacitors C_3 and C_4 will be: 1/C_34 = 1/C_3 + 1/C_4 Therefore 1/C_34 = 1/3 + 1/6 Therefore 1/C_34 = 2 + 1/6 Therefore 1/C_34 = 3/6 Therefore 1/C_34 = 1/2 Therefore C_34 = 2 rightarrow Now, capacitors