Question

calculate the molarity of a 15% (by mass) aqueous solution of hydrochloric acid.
Answer choices:
(a) 0.0274m
(b) 0.274m
(c) 3.05m
(d) 4.84m
(e) the density of the solution is needed to solve the problem

Answer 1

15). (by max) = Max of solute X100 mas Solution it means isg of solute (HU) in 100g of H20. Density of H₂D is 1 g/mL. na volume of solution = mole HU= Given 15g loomL. OO of may Molar mas 0.4109 mole. 36.5 Molarity = moles ogmoft vol of solution (me) x1000 g Solute 4.109 M 0.4109 x 1000 1000 Answer is not matching It means, densely we have taken it is wrong. Therefore, last option is correct answer. # Consity of solution is needed