) Arrange the running time of functions mentioned below by the order (increasing) of their growth.
n^3 , n, nlog(n) , log(n), 2^n, n^2, n!
my guess without doing the math is:
n
nlog(n)
log(n)
n^2
n^3
2^n
n!
The best way to answer this question would be taking 2-3 test cases, having n greater than, say, 20
-----------------------------
So, for n = 20
-----------------------------
n^3 = 8000
n = 20
nlog(n) = 59.915
log(n) = 2.996
2^n = 1048576
n ^ 2 = 400
n! = 2.4329 x 10^18
---------------------------------
So as per the observation, the ascending order is,
log(n)
n
nlog(n)
n^2
n^3
2^n
n!
NOTE:- Order may vary as per extreme values, but this will be valid for majority of the numbers to a great extent
) Arrange the running time of functions mentioned below by the order (increasing) of their growth....
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Here are some common orders of growth, ranked from no growth to
fastest growth:
Θ(1) — constant time takes the same amount of time regardless
of input size
Θ(log n) — logarithmic time
Θ(n) — linear time
Θ(n log n) — linearithmic time
Θ(n2 ) — quadratic time
Θ(n3 ), etc. — polynomial time
Θ(2n), Θ(3n), etc. — exponential time
(considered “intractable”; these are really, really horrible)
In addition, some programs will never terminate if they get
stuck in an...