Question

Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation

H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2

If you require 33.38 mL of 0.1936 M N a O H N a O H solution to titrate 10.0 mL of H C 2 H 3 O 2 H C 2 H 3 O 2 solution,

what is the molar concentration of acetic acid in the vinegar?

Answer 1

CH₃COOH + NaOH CH₃COONa + H₂O

one mole of acetic acid is neutralized by NaOH

Molarity ( NaOH ) X Volume ( NaOH ) =Molarity ( Acetic acid ) X Volume ( acetic acid )

0.1936 M X 33.38 mL = Molarity ( Acetic acid ) X 10 mL

Molarity ( Acetic acid ) = 0.646 M

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