Question

write a function which takes a string argument and a character argument. It should return a truth value (int 0 or 1), 0 if the string does not contain the character, and 1 if the string does contain the character. Do not use a built-in library for this. Again, call this function and its variables whatever you deem appropriate. The main function of the program should accept a single character followed by Enter. Then, it will read lines until the end of input (we'll call that EOF from now on). It should pass these lines to the function you wrote. If the character is in the line, it should print "FOUND: " and then the full line. If the character is not in the line, it should print "NOT FOUND: " and then the line. Assume lines of input are no longer than 1000 bytes in length. Also, make sure that your program can accept an arbitrary number of lines of input. Either 5, 10, 90, or 1000 lines of input can be given after the first character and it should still work as intended even if you gave the program more input. Again, signal the EOF with CTRL+D. You should only need one buffer

Answer 1

import java.io.IOException;

import java.util.Scanner;

public class Driver{

public static void main(String args[]) throws IOException{

System.out.println("Enter the char ");

char c = (char) System.in.read();

Scanner in = new Scanner(System.in);

in.nextLine();

System.out.println("Enter a String");

String str = in.nextLine();

if(isFound(str, c) == 1)

System.out.println("FOUND");

else

System.out.println("NOT FOUND");

}

private static int isFound(String str, char c) {

for(int i = 0; i < str.length(); i++)

if(str.charAt(i) == c)

return 1;

return 0;

}

}

**Comment for any further queries.