Question

C++ beginners coding:

Nested loop, Do-While

Code for problem: Until the user wants to quit (by typing "q" or "Q") assume there is a # (assuming it's positive), print all multiple of 3 from 3 to their #. The user should be asked to quit only after one run of the program.

Answer 1

Solution:

Code:

//Include necessary headers #include <iostream> using namespace std; //Main method int main() /*Declare necessary variables*/ int number, val; char sentinal; /*Nested do...while loop*/ do /*Prompt and get input/ cout<<"Enter the positive value:"; cin>>number; //Print statement cout<<"Values are: \n"; int i=1; /*Do...while loop*/ do //Calculation val=i*3; // Condition if(val<=number) //Print the result cout<<val<<endl; i++; //Condition for the loop while(val<number); /*Prompt and get for quits/ cout<<"Do you want to continue(Q/9):";

cin>>sentinal; //Loop condition while( sentinal!='q' && sentinal!='0');

Output:

2./main Enter the positive value: 5 Values are: Do you want to continue (0/9):n Enter the positive value:9 Values are: 9 Do you want to continue (Q/g):n Enter the positive value:15 Values are: 9 12 15 Do you want to continue (Q/g):n Enter the positive value:30 Values are: 27 30 Do you want to continue (Q/g):9

Copyable Code:

//Include necessary headers

#include <iostream>

using namespace std;

//Main method

int main()

{

/*Declare necessary variables*/

int number,val;

char sentinal;

/*Nested do...while loop*/

do

{

/*Prompt and get input*/

cout<<"Enter the positive value:";

cin>>number;

//Print statement

cout<<"Values are:\n";

int i=1;

/*Do...while loop*/

do

{

//Calculation

val=i*3;

//Condition

if(val<=number)

{

//Print the result

cout<<val<<endl;

}

i++;

}

//Condition for the loop

while(val<number);

/*Prompt and get for quit*/

cout<<"Do you want to continue(Q/q):";

cin>>sentinal;

}

//Loop condition

while(sentinal!='q' && sentinal!='Q');

}