Question

Problem 9 Based on the bode plot, what is the filter type? What is the cutoff frequency of the filter in Hertz, w ? Draw a circuit that could produce this bode plot and label all the circuit component values. Problem 10 Based on the bode plot, what is the filter type? What is the cutoff frequency of the filter in Hertz, wc? Draw a circuit that could produce this bode plot and label all the circuit component values.

Answer 1

solution:

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9)

For low frequencies gain is high and for high frequencies gain is high. So it is passing low forequencies and attenuating high frequencies. Therefore it is low pass filter → cut off frequency is where gain decreas- -es by 3 dB from manimum gain. is gain lode, 10-3 = 768 Here Maximum gain at lo' Hz. = 6.28 x 10 - cut off frequency = w: 2 IT f :62.Yed's → phase is 180 amplifier. from bode plot, at DC means it is investing he to Vout X < A DC gain = - R2 = 10 a R2 = lor, R lok then R2 = 1oxlk KR Let B Gain - - Grain : - - - cutoff freg: zet Ruc .10 ASCR₂ SCR = 1.59 4H 2TX 10X 10K Ri=1K2, Bylo kr, 159MH.

10)

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At low frequencies less gain and at a gain. So, it is high bigh a frequencies requencies high high pass filter... → Cutoff frequency where gain less +3dB of maximum gain, cor phase change is 450 then at 1 102 Hz phase changes from -90 to -1350 then Cutoff frequency ewe = 10² x 2T = 628 orad I see 180° then → At high iz is a frequencies invesiting phase is amplifien. Vout LP → Cutoff frequenly = I 2T Rica at High frequency gain = R = 30 R2 - 30R R = 30 kn Rilke, fc: C framac 2100 - 210o - 21 X 100IK ZRC : : 1.594F Ri= lkr, R2 = 30kr, c, = 1.59 MF.