Question

Using a Taylor expansion up to second order in s/d and s2l/d, show that in the limit of large d the term AH in eqn 4.27 becom
Si =rı + duc/2, S2 = r2 - duz/2.
1 - (4.27) ra – r r - duy/2 r2 + du/2
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Answer #1

Si= sit dux 2 Az - dos (8-2) = (1, -83) + duxe ->r, - r2 = (81- se) - dun in stare un Ini - x 19-4. - and djur-f-41 -du-(4-41

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