Question

8. Two long straight wires pass through x and x = 7 cm and each carry currents of 8 A as 3 cm shown in the figure. a) What is the value of the magnetic field at the origin? (Be sure to specify direction.) b) What is the force on a 5 pc charge at the origin moving with a velocity of (1500 ) mus? c) In order for a charge at the origin to feel no magnetic force, what is one possible direction could be moving?

Answer 1

Kuum K cm TX I- 8A o is the origin at which we have to find magnetic field. Magnetic field due to o wire. MOI, B, do I coutwards. Do. 21TXB) ' towards you) 2 ) (Outwards 9 to Osc A 800) As the direction of both B, J By is same then the total magnetic field cet o is, x

field Im B Tem bom cet o is, - Bit By do I tho I 20 (3) 25 (7) - 4o I \оо 25 fout of the plane of bapers (5-8) 1] = 2x4 X163 XI [ 2 ] x100 B = 160x16 X 107 X10 = 7.62x165 - ЧТІ ХТО Glo=UT 1

® if a charge of magnitude suc is placed cet 3. & with it is moving V-1500 ins. means it is moving in the e direction. I Now, At a magnetic is out of plane ie (tz cexis), hence the motion cef charge particle to is perpendicolor the direction it of B will so that experience magnitude: a force having f = q CüxⓇ) E qUB sino 10=72).

P = q (DXB) : QUB sino 10=5/2). f qVB (downwards. Put the values (y axis) f = 5x10 6 x 1500 27.62x105 = 57150x1011n = 57150 110000 XIO" N. 10000 5-7150 x 16 7 x 7 © The charge should direction move in ch magnetic field ie (0-0) the F- QUB sino =0 In tz direction. So