Question

GLOBAL A Mare out of bodo Question 2 Hagestion Write a C++ program to generate two random integers x and y in the range 10 to 40 such that x <y. The program should prompt the user to choose from the following menu: (8 points) 1. Calculate and output the percentage of perfect numbers between 1 and x (10 points) 2. Calculate and output the average of odd divisors of x. (8 points) 3. Calculate and output the value of f(x): x/y + x/y2 + x/y + ...+x/y (8 points) 4. Check how many palindrome numbers exist between x and y and output their sum (10 points) 5. Exit (2 points) The program should loop on the above menu till the user selects 5 to exit. (4 points) A - B 1 1 - E x x il ali U

Answer 1

#include<bits/stdc++.h>
using namespace std;
int main(){
int x,y,n,i,j;
int a=rand()%31+10; //generating random numbers rand()%31 gives numbers from 0 to 30
int b=rand()%31+10; //so 10 added for ranging from 10 to 40
if(a<b){ x=a; y=b;}
else{ x=b; y=a; }
cout<<"x : "<<x<<endl; cout<<"y : "<<y<<endl;
while(1){
cout<<"Enter option, press 5 for exit : "; cin>>n;
if(n==5) break;
else if(n==1){ //check no of perfect no from 1 to x
int c1=0;
for(j=1;j<=x;j++){
int sum1=0;
for (i=1;i<=j;i++)
if (j%i==0) sum1+=i;
if(j==sum1) c1++;
}
cout<<"Percentage of perfect no from 1 to "<<x<<" is : "<<(c1*100.0/x)<<endl;
}
else if(n==2){ //no of odd divisors of x
int sum2=0,c2=0;
for (i=1;i<=x;i++) {
if (n%i==0 && i%2==1){
sum2+=i;
c2++;
}
}
cout<<"Average of odd divisors of "<<x<<" : "<<(1.0*sum2/c2)<<endl;
}
else if(n==3){ //calculate sum of series
double sum3=0;
for(i=1;i<=x;i++) sum3+=1.0*x/pow(y,x);
cout<<"Sum of the series is : "<<sum3<<endl;
}
else if(n==4){ // no of palindrome no between x to y and their sum
int c=0,sum4=0;
for(i=x;i<=y;i++)
if(i%10== i/10){
c++;
sum4+=i;
}
cout<<"Total "<<c<<" numbers are palindrome and sum of palindrome numbers is "<<sum4<<endl;
}
else{
cout<<"Entered wrong option."<<endl;
}
}
return 0;
}

WN } } 1 #include<bits/stdc++.h> 2 using namespace std; 3- int main(ok 4 int x,y,n,i,j; 5 int a=rand()%31+10; //generating random numbers rand()%31 gives numbers from a to 30 6 int b=rand()%31+10; //so 10 added for ranging from 10 to 40 7 if(a<b>{ x=a; y=b;} 8 else{ x=b; y=a; } 9 cout<<"x:"<x<<endl; cout<<"y : "<<y<<endl; 10 while(1) { 11 cout<<"Enter option, press 5 for exit : "; cin>>n; 12 if(n==5) break; 13 else if(n==1){ //check no of perfect no from 1 to x 14 int c1=0; 15. for(j=1;j<=x;j++{ 16 int sum1=0; 17 for (i=1;i<=j;i++) 18 if (j%i==0) sum1+=i; 19 if(j==sum1) c1++; 20 21 cout<<"Percentage of perfect no from 1 to "<<x<<" is : "<<(c1*100.0/x)<<endl; 22 23 else if(n==2){ //no of odd divisors of x 24 int sum2=0,c2=0; 25 for (i=1;i<=x;i++) { 26 if (n%i==0 && i%2==1) { 27 sum2+=i; 28 c2++; 29 30 31 cout<<"Average of odd divisors of "<<(1.0*sum2/c2)<<endl; 32 33 else if(n==3){ //calculate sum of series 34 double sum3=0; 35 for(i=1;i<=x;i++) sum3+=1.0*x/pow(y,x); 36 cout<<"Sum of the series is : "<<sum3<<endl; 37 38 else if(n==4){ // no of palindrome no between x to y and their sum 39 int c=0,sum4=0; 40 for(i=x;i<=y;i++) 41 if(i%10== i/10){ 42 C++; 43 sum4+=i; 44 45 cout<<"Total "<<<<<" numbers are palindrome and sum of palindrome numbers is "<<sum4<<endl; 46 47 - else{ 48 cout<<"Entered wrong option."<<endl; 49 50 co نہا لها } } } } بها نها

x : 15 Y : 20 Enter option, press 5 for exit : 1 Percentage of perfect no from 1 to 15 is : 6.66667 Enter option, press 5 for exit : 2 Average of odd divisors of 15 : 1 Enter option, press 5 for exit : 3 Sum of the series is : 6.86646e-18 Enter option, press 5 for exit : 4 Total 0 numbers are palindrome and sum of palindrome numbers is 0 Enter option, press 5 for exit : 5 < ... Program finished with exit code 0 Press ENTER to exit console..