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In the figure shown below, there is a rectangular load distribution acting on the beam. Calculate:...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. w lb/ft aft L ft aft COLLAPSE IMAGES w = 480 lb/ft L = 13 ft 9 = 2 ft Calculate the support reaction Ay lb ENTER 3 tries remaining. 1 point(s) possible Calculate the support reaction Ax lb ENTER 3 tries remaining. 1 point(3) possible Calculate the support...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. Calculate w lb/ft PID Mb.ft с Lft B a ft bft COLLAPSE IMAGES w = 140 lb/ft P= 200 lb L = 7 ft a = 4 ft b = 4 ft M = 80 lb.ft The vertical reaction at A. (Ay) ID ENTER 3 tries remaining. 1 point(3)...
For the beam show, calculate: w lb/ft p lb/ft L ft aft bft COLLAPSE IMAGES w = 80 lb/ft p = 40 lb/ft L = 8 ft a = 8 ft b= 6 ft The vertical reaction at A. Іь ENTER 3 tries remaining. 1 point(3) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(3) possible The range for section 1. ) ft ENTER 3 tries remaining. 1 point(3) possible The shear force equation for section...
The hook and spring assembly shown in the figure are equilibrium, calculate: F. lb k lb/ft А (1) Falb В 02 2 ft F3 lb COLLAPSE IMAGES F1 = 110 lb F3 = 52 lb 01 - 21 deg 02 - 35 deg k = 1506 lb/ F2 = 98 lb The magnitude of the resultant force. Ib ENTER 3 tries remaining. 1 points) possible The orientation counter-clockwise from the positive x axis of the spring. deg ENTER 3 tries...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. W lb A Lft Lft COLLAPSE IMAGES W = 248 lb L = 7 Calculate the vertical reaction (Ay) at support A ID ENTER 3 tries remaining. 1 point(3) possible Calculate the horizontal reaction (Ax) at support A ID ENTER 3 tries remaining, 1 point(s) possible Calculate the vertical...
The truss is supported by wheels at A and a hinge at B and subjected to 2 equal vertical forces P lb at C and G, and a horizontal force P lb at D. Draw the reactions in the positive coordinate directions. P lb y L ft P lb D X A Lft L ft P lb COLLAPSE IMAGES P 175 lb L5 ft The x component of the reaction at A, Ax. ENTER 3 tries remaining 1 point(s) possible...
The x component of the support reaction at A, Ax: 10 / 10 pts System Answer: 0 The y component of the support reaction at 10/10 pts System Answer: 214.8 The y component of the support reaction at B, By. 10 / 10 pts System Answer: 219.2 The shear force equation for section 1. 1 6 ENTER ENTER * 2 tries remaining. 15 point(s) possible The bending moment equation for section 1. ENTER 3 tries remaining. 20 point(s) possible Q1...
For the beam shown, draw the reactions at supports A and B in the positive direction, and also draw the shear and bending moment in the positive direction on your FBD. kip ft B L/3 ft Lft COLLAPSE IMAGES w = 17 kipiift L = 9 ft The vertical reaction at support A. (Ay) kip ENTER 3 tries remaining. 1 point(3) possible The horizontal reaction at support A. (Ax) kip ENTER 3 tries remaining. 1 point(s) possible The vertical reaction...
Q3 Weight: 20.00% Consider the beam below: w lb/ft Wlb h ft M lb-ft w ---HI bft Cross section EE COLLAPSE IMAGES W = 62 lb/ft W= 139 lb /y = 7 ft 12 =2 ft b = 0.5ft h = 0.1 ft M = 127 lb.ft int.com/#!/assessment/2015/247/Homework%2013 The vertical reaction at A. lb ENTER 3 tries remaining. 1 points) possible The horizontal reaction at A 1/1 pts 0 lb System Answer 0 The vertical reaction at B. lb ENTER...