Question

punu ile 20 maze from chapter 12. 2. StringToolong.java → Write a program that creates an exception class called StringTooLongException, designed to be thrown when a string is discovered that too many characters in it. In the main driver of the program, read strings from th user until the user enters "DONE". If a string is entered that has too many chara (say 20), throw the exception. Allow the thrown exception to terminate the program.

java

Answer 1

import java.util.Scanner;

//exception class for long string
class StringTooLongException extends Exception
{
public StringTooLongException()
{
//display message on the computer screen
super("The string has more than 20 characters");   
}
}

public class Main
{
public static void main(String[] args) throws StringTooLongException
{
//variable declaration and initialization
int maxLength = 20;
String inputString;
  
Scanner input = new Scanner(System.in);
  
while(true)
{
//try block
try
{
//display message on the computer screen
System.out.println("Enter a string (enter DONE to finish): ");
inputString = input.nextLine();
  
if(inputString.equalsIgnoreCase("DONE"))
{
return;
}
  
if(inputString.length()>maxLength)
{
throw new StringTooLongException();
}
  
}
  
//catch block
catch(StringTooLongException e)
{
System.out.println(e.getMessage());
}
}
}
}

OUTPUT:

Enter a string (enter DONE to finish): hello hi Enter a string (enter DONE to finish): hello hi hello hi hello hi The string has more than 20 characters Enter a string (enter DONE to finish): done