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a) torque = I x alpha
torque is r x F .
(1.5 * 100 * sin90) - ( 0.8 *150 *sin40) = (25 *2^2 / 3) * alpha
alpha = 2.19 rad/s^2
b) angular momentum = I w
= (25 * 2^2 / 3) * 25 = 833.33 kg m^2 /s
c) KE = Iw^2 /2 = ( 25* 2^2 / 3) * (25^2) / 2 = 10416.67 J
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