Question

Hello, I am taking an electrical engineering lab course and I really need help understanding the solution to this question:

2. (2 points) Consider the push-pull amp sketched below. Let (t) = sin(21000) volts. (Thus the period is 1ms). Carefully sketch on the grid below the expected appearance of the output voltage (I). Please note the period is loos Please label important amplitudes on the y-axis. O +15V 6-157 Av -0,6V = 6V-0.6V=5,41 ott 04 + + Como) - Avto.6V = -6V + 0.6V=- 5,4V .

Now this solution was marked as correct. Here are my questions:

1) Could you please explain how they obtains the gain (Av) of 6 V?

2) Why did they substract 0.6 V from the gain?

If you could walk me through this solution step-by-step, I would really appreciate it, thank you.

Answer 1

and for the negative cycle its reverse( means lower one is on and upper one is off)

find the attached solution

Cheers!!!

aus ③ book here Ay doesn't means goin its actually the magnitude of inbut applied signal @ ' If you see the diagram for Positives cycle the upper (npn) transistor is active and (P18) houer i torned off ro vo= vin rotor where as of is taken as VBG Voltage