Total sample size = 30,300,000 + 500,000 + 3000 + 100 = 30,803,100
a)
Probability of delivering twins = 500,000 / 30,803,100 = 0.01623
b)
Probability of delivering quadruplets = 100 / 30,803,100 = 3.25 x 10-6 = 0.00000325
c)
Probability of delivering more than a single child = (500,000 + 3,000 + 100) / 30,803,100 = 503,100 / 30,803,100
= 0.01633
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(2.3) C >= S-Ee^(-rT)
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The question is labelled W.26. Thank you!
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