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Consider a half circle of wire carrying a current 4.3 A (for the purposes of this problem, we will ignore what happens to the

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Solution I = 4.3 A Magnetic field at centre due to semicircular loop 5 mm 1دد B = 4R B 40TX10-7 u X 403 4* 5x10-3 B = 0.27 mT

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