Question

C++ SECTION 1) (15 points) Write a full C++ program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. The output of the program is every word in the list that contains the character at least once. Assume at least one word in the list will contain the given character. Ex: If the input is: 4 hello zoo sleep drizzle z then the output is: 200 drizzle To achieve the above, first read the list into a vector of strings. Use a string method to find the character in the strings. You will also need to keep in mind that the character 'a' is not equal to the character 'A'. The code has been started for you.(Lecture 12 - String searching) #include ciostream> #include cvector> using namespace std; int main() { int i; int numWords; vector<string> inputWords; char searchcharacter; string userInput: unsigned int ): // Integer indicating the number of words that follow cin >> numklords; return 0;

Answer 1

Please find the solution below. Added comments for better understanding of the program. Also attached screenshot of the program run.

C++ Source Code

#include <iostream>
#include <vector>

using namespace std;

int main() {

int i;
int numWords;
vector < string > inputWords;
char searchCharacter;
string userInput;
unsigned int j;

cin >> numWords;

// Take user input for list of words and store into the vector - inputWords
for (j = 0; j < numWords; j++) {
cin >> userInput;
inputWords.push_back(userInput);
}

// Take user input for character to be searched
cin >> searchCharacter;

// For each word in vector - inputWords, check if searchCharacter is present or not
for (j = 0; j < numWords; j++) {
// Check whether searchCharacter is present or found in inputWords[j] using string method - find()
if (inputWords[j].find(searchCharacter) != string::npos) {
cout << inputWords[j] << endl;
}
}

return 0;
}

Output

4 hello zoo sleep drizzle z zoo drizzle - - -- - - - Process exited after 17.01 seconds with return value o Press any key to continue ...