(40 )-
in this case , force due to deceleration will be equal to frictional force,
ie,
Fa= Ff
m a = u mg , where u is frictional constant
a= u g
a= 0.75 x 9.8 = 7.35 m/s^2
maximum rate = 7.35 m/s^2
need help with number 40 wuatis thco eent OI Knetic inctOn 38. (I) Suppose you are...
The coefficient of static friction between hard rubber and normal street pavement is about 0.4. On how steep a hill (maximum angle) can you leave a car parked?
I just need help with part C please! I'm struggling! Thank
you.
a) If half of the weight of a flatbed truck is supported by its two
drive wheels, what is the maximum acceleration (in m/s^2) it can
achieve on dry concrete where the coefficient of kinetic friction
is 0.7 and the coefficient of static friction is 1.
The answer is 4.9 m/s^2.
b) Will a metal cabinet lying on the wooden bed if the truck
slip if it accelerates...