Question

4. Provide proper and consistent units for all dimensional quantities. Convert at the units if necessary. Omission or incorrect usage of units will cause grade reduction 5. Your solution should be readable. Neatness will be graded. 6. Cite all the references you used for the solution of the problems, such as, tables, figures appendices, other books, internet, etc. 7. The following information must be provided on the submitted homework: Name. Last name, ID number QI) A cylindrical vessel containing nuclear waste is buried deep in the ground for disposal. The container has an outside diameter of D, 1m, a length of L=10m, and is made of 2.5cm thick lead. If the container is buried too shallow there is a risk of radiation contamination, but if it is buried too deep, there is a risk of the container becoming too hot and the lead shell melting. At what depth should the container be buried if the radioactive waste generates 2600 W of heat and the surface temperature of the ground is constant at 25°C Q2) A very long stainless steel bar with a square cross section is subjected to constant temperature boundary condition on 3 sides and a convective environment on one side as shown in the Figure. The convective heat transfer coefficient, h=300 W/m2.K and T. 5°C. Using the grid shown, calculate all the unknown nodal temperatures. T T = 0°C h, 7 * 7 = 100°C T = 0°C

Answer 1

Solution for both (Q1. And Q2. Are mentioned below)

था Solution -> IT outed dia (do) Flm i Lelom. ; t = 2.5 cm di=0.95m ; K = 0.52 W/mke. To = 25°C Q = 2600 W → Q = 57/ in ( do/di) .:2600 = IL - TO : D Ti-To = 4.083 283-14 mo.solo instan ? 14.033*232 IT, = 29.0832 Alou, T = Twt qa [Ro-o] AN s 29.083 - 05 + 2600 3:14x14x10[4X0:52) C o iste 0-10 ~ re 0.5-0.1 :8= oam Now (d'] d'= Roar 0.5 -0.4 = d .. d = o-lom Lois-y] at the b! = 10 com]

TO T T TA Ginen 4= 300w/mzu k=45 W/mk 1 100°C o .tm falso lqe' 18' TA' L=001 TR=Sc) Rolec les e " Ituale M estial aquinaht a 5c -youw ood 1. Req = Reput Road :-Req = 0.055 Resporre so = = 0.114 a 8.133 81094. 1. Rond. + KA 300701 45x04 n. 300* OT two to vote for spe cies are o > 100 -14 100-S 0.055 235x10 + 100-TA' = A' - Te! :: TA: 100-4-425 ir TA = 98.57°c) Similarly 601 learco are sane) :. TB = q*98157 -100 i To = 99.14°C Similarly Te = 9507100 (equately Tc & TB). & soularly from TE&TD egins we get To = 94.28°C