Question

Q)Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch hour. To evaluate the program, he selected a random sample of eight participants and found the number of days each was absent in the six months before the exercise program began and in the six months following the exercise program. Below are the results.

Employee	Before	After
1	6	2
2	7	6
3	7	4
4	6	7
5	4	5
6	7	3
7	5	3
8	5	2

At the 0.100 significance level, can he conclude that the number of absences has declined? Estimate the p-value.

Q1)State the decision rule for 0.100 significance level. (Round your answer to 3 decimal places.)

Reject H0 if t >

Q2)Compute the test statistic. (Round your answer to 3 decimal places.)

Q3)The p-value is (Which of The following)

Between 0.01 and 0.025

Between 0.001 and 0.005

Between 0.005 and 0.01

Q4)State your decision about the null hypothesis.

Reject H0

Do not reject H0

Answer 1

null Hypothesis alternate Hypothesis ud 0 ud 0 for 0.1 level with right tailed test and n-1- 7 degree of freedom, critical value of t- Decision rule 1.415 reject Ho if test statistic t>1.415 difference(d) x1-x2 4 element Before After 16.000000 1.000000 9.000000 1.000000 1.000000 16.000000 4.000000 9.000000 4. 4 2 total mean dbar- degree of freedom -n-1 Std deviaiton Sp-V(Ed2-(2d)2/n)/(n-1) std error-Se SDVn 1.875 7.000 2.0300 0.718 t stat 2.61

1)

reject Ho if t>1.415

2)test statistic t =2.611  

3) Between 0.01 and 0.025

4)Reject H0