Question

The electrolysis of molten AlCl_3 for 1.00 hr with
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Answer #1

charge supplied = current * time

=15*60*60

=54000 C

one mole of Al3+ requires 3 farad of charge.

so moles of Al formed = (54000)/(3*96500)

=0.1865

~0.187 moles=5.04 grams

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