charge supplied = current * time
=15*60*60
=54000 C
one mole of Al3+ requires 3 farad of charge.
so moles of Al formed = (54000)/(3*96500)
=0.1865
~0.187 moles=5.04 grams
The electrolysis of molten AlCl_3 for 1.00 hr with an electrical current of 15.0 A produce...
The electrolysis of molten AICI, for 3.25 hr with an electrical current of 15.0 A produces g of aluminum metal. O 4.55 x 103 16.4 49.1 0.606 147 Submit Request Answer
um CollUl exceed 100%. Calculate the grams of aluminum metal produced from the electrolysis one hr with an electrical current of 15.0 amperes. al produced from the electrolysis of molten AlCl3 for 3.25 electrical current of 15.0 amperes. Work must be shown to receive credit. 6 points
aluminum produced in 1.00 h by the electrolysis of molten AICI if the current is 10,0 AN A It Belz ZAICI, 60 seconds 10 A 22600] =36,000 Aus=C 36,000 c. Zmolal E Imole- 27 = 20.15g 3.36 20.15 gal
aluminum produced in 1.00 h by the electrolysis of molten AICI if the current is 10,0 AN A It Belz ZAICI, 60 seconds 10 A 22600] =36,000 Aus=C 36,000 c. Zmolal E Imole- 27 = 20.15g 3.36 20.15 gal
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