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A random sample of 15 students of a certain college an average 78.5 words per minute with a standard deviation of 8.2 words p
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Solutaon Gaven: L=1% n=15 X= 78.5 , = 8.2 99% prediction intervay as I t212,0 x x Jr ( 78.5 I tooos, 15 Х 8.2 JIG a) f 78.5 +

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