Calculate the equilibrium concentrations of C2HsCOO and C2HsCOOH in a solution prepare by dissolving 0.04 mole...

Question

Question

Calculate the equilibrium concentrations of C2HsCOO and C2HsCOOH in a solution prepare by dissolving 0.04 mole of propionic acid in 150 ml of water.

science chemistry

Answer 1

Answer #1

molarity of C2H5COOH = no of moles/volume in L

=0.04/0.15 = 0.267M

C2H5COOH (aq)--------------> C2H5COO^- (aq) + H^+(aq)

I 0.267 0 0

C -x +x +x

E 0.267-x +x +x

Ka = [C2H5COO^-][H^+]/[C2H5COOH]

1.34*10^-5 = x*x/0.267-x

1.34*10^-5 *(0.267-x) = x^2

x = 0.0019

[C2H5COO^-] = x = 0.0019M

[H^+] = x = 0.0019M

[C2H5COOH] = 0.267-x = 0.267-0.0019 = 0.265M

Answer 2

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