Homework Answers
a)
compression = 12 cm
= 0.12 m
use,
potential energy = 0.5*k*(compression)^2
= 0.5*384*(0.12)^2
= 2.76 J
b)
when ball will be launched
potential energy of spring will get transmited as kinetic energy of
ball
so,
0.5*m*v^2 = potential energy
0.5*0.135*v^2 = 2.76
v^2 = 40.9
v = 6.39 m/s
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