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Let X be a random variable with finite mean mu and such that E[(X - mu)^2]...

Let X be a random variable with finite mean mu and such that E[(X - mu)^2] is finite. Then the variance of X is defined to be E[(X - mu)^2], denoted as sigma^2. Using this expected value expression: sigma^2 = E[(X - mu)^2], show that the variance, sigma^2 = E(X^2) - mu^2

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