Question

Suppose X ~ N(2, 3). What value of x has a z-score of -0.67?  

If the area to the left of x in a normal distribution is 0.161, what is the area to the right of X?  

Answer 1

Answer 2

ANSWER :

54

x = N(µ, var.) = N(2, 3)

=> µ = 2 and var. = 3 

=> s = SD = sqrt(var) = sqrt(3) = 1.732 

z score = (x - µ)/s = (x - 2)/1.732  

=> - 0.67 = (x -2)/1.732

=> x = -0.67*1.732 + 2 = 0.8396 (ANSWER).

55

Area to the right 

= 1 - area to the left

= 1 - 0.161

= 0.839 (ANSWER)