If I sum a binomial random variable with n=5 and p =0.3 and a binomial random...
If I sum a binomial random variable with n=5 and p =0.3 and a binomial random variable with m=10 and p =0.5, I get
Select one:
a. Something unfamiliar to us as yet
b. A normal distribution
c. A binomial random variable with number of Bernoulli trials =15 and p =0.4
d. A Binomial with number of Bernoulli trials =15 and p=0.4
Homework Answers
a. Something unfamiliar to us as yet
The binomial distributions add to for another binomial distribution if the probability of success, p is same for both distributions that are to be added. here, p is different for the two binomial random variables and hence it forms some discrete distribution which cannot be classified as any of the option given here.
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If I sum a binomial random variable with n=5 and p =0.3 and a
binomial random...
5.a. Usining Binomial probability distribution formula for a random variable X, compute Where N= 15, p=0.3...
5.a. Usining Binomial probability distribution formula for a random variable X, compute Where N= 15, p=0.3 and find P(x=2)? Begin P(X=2) =
help 5.a. Usining Binomial probability distribution formula for a random variable X, compute Where N=15, p=0.3...
help
5.a. Usining Binomial probability distribution formula for a random variable X, compute Where N=15, p=0.3 and find P(x=2)? Begin PIX=2) =
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5.a. Usining Binomial probability distribution formula for a random variable X, compute Where N= 15, p=0.3 and find P(x=2)? Begin P(X=2) =
help
5.a. Usining Binomial probability distribution formula for a random variable X, compute Where N=15, p=0.3 and find P(x=2)? Begin PIX=2) =
1. Imagine a coin toss experiment, where P(Heads)-P(Tails) 0.5. Define a random variable of your choice for this experiment and come up formulation for a question about this experiment, so that The distribution of a random variable for this experiment follows a binomial distribution The distribution of a random variable for this experiment follows a geometric distribution a. b. Note: you are only required to come up with the problem statement. Note, that this experiment itself is a Bernoulli trial....
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