QUESTION 6 In the balanced redox reaction below, 16H* (aq) + 2 MnO4 (aq) +502042-(aq) +...

Question

Question

science chemistry

Answer 1

Answer #1

What atom is reduced?

Answer D (Mn atom is reduced as it's oxidation number is reduced from +7 to +2)

What reactant is the reducing agent?

Answer B (C2O42-)

Add a comment

Answer 2

Similar Homework Help Questions

Problem Page Write balanced half-reactions for the following redox reaction: 2MnO−4 (aq) + 16H+ (aq) +...

Problem Page Write balanced half-reactions for the following redox reaction: 2MnO−4 (aq) + 16H+ (aq) + 10Cl− (aq) → 2Mn+2 (aq) + 8H2O (l) + 5Cl2 (g) reduction: oxidation: e
Write balanced half-reactions for the following redox reaction: 10CO2(aq)+2Mn+2(aq)+8H2O(l)→ 5C2O−24(aq)+2MnO−4(aq)+16H+(aq) Oxiadtion Reduction

Write balanced half-reactions for the following redox reaction: 10CO2(aq)+2Mn+2(aq)+8H2O(l)→ 5C2O−24(aq)+2MnO−4(aq)+16H+(aq) Oxiadtion Reduction
Redox. For each reaction below: 1) Ensure that the reaction is balanced. 2) Assign oxidation numbers...

Redox. For each reaction below: 1) Ensure that the reaction is balanced. 2) Assign oxidation numbers to each reactant and product 3) Identify which atom was oxidized and which atom was reduced. 4) Identity which atom is the oxidizing agent, and which is the reducing agent A) Br2(l)+I^-(aq) --->Br^-(aq)+I2(s) B)Cr2O7^2-(aq)+Fe^2+(aq)--->Cr^3+(aq)+Fe^3+(aq) C) NO3^-(aq)+I2(aq)--->IO3^-(aq)+NO2(aq)

a Choose the balanced equation for the following half-reaction, which takes place in acidic solution MnO4...

a Choose the balanced equation for the following half-reaction, which takes place in acidic solution MnO4 (aq)Se2 (aq) -> Mn2(aq) Se(s) O 16H (aq)2Mn04- (aq)5Se2 (aq) ->2Mn2 (aq) 6H20()5Se(s) O16H (aq)2MnO4- (aq)5Se2 (aq) -2Mn2 (aq) 8H20(1) 5Se(s) 16H+ (aq)MnO4 (aq) 5Se2(aq) - Mn2(aq) +8H20(l) 5Se(s) O16H (aq)MnO4- (aq) 5Se2 (aq) -2Mn2(aq) + 8H2O(l)5Se(s) bChoose the balanced equation for the following half-reaction, which takes place in acidic solution: S2Os2(aq)CI (aq) SO42(aq) Cl2 (aq) S2O82(aq)2CI (aq) 2SO42(aq) Cl2(aq) S2O82-(aq)C (aq) -2SO42-(aq) 2Cl2...
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: 2MnO4-(aq)...

A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: 2MnO4-(aq) + 16H+(aq) + 5Pb(s) -> 2Mn2+(aq) + 8H2O(l) + 5Pb2+(aq) Suppose the cell is prepared with 2.08M MnO4- and 1.77M H+ in one half-cell and 1.82M Mn2+ and 1.13M Pb2+ in the other. Calculate the cell voltage under these conditions. Do not round intermediate calculations. Round your answer to 3 significant digits.
Write balanced half-reactions for the following redox reaction: MnO4^-(aq) + 4H2O(l) + 5Cu^+(aq) = Mn^2+(g) +...

Write balanced half-reactions for the following redox reaction: MnO4^-(aq) + 4H2O(l) + 5Cu^+(aq) = Mn^2+(g) + 8OH^-(aq) +5Cu^2+(aq)

4. Consider the following unbalanced net redox equation: HCI + KMnO, (aq) + H,02 (aq) -. MnC12 (a...

PLEASE ANSWER EACH QUESTION OR DO NOT ANSWER AT ALL. THANK YOU! 4. Consider the following unbalanced net redox equation: HCI + KMnO, (aq) + H,02 (aq) -. MnC12 (aq) + O2 (g) + KCI in an acid solution a. Determine the oxidation state of each atom or ion in the above reaction: b. Which atom is being oxidized? Which atom is being reduced? C. Which species is the reducing agent? Which is the oxidizing agent? d. Write the net...
A galvanic cell is powered by the following redox reaction: 2 MnO2 (aq) + 16H+ (aq)...

A galvanic cell is powered by the following redox reaction: 2 MnO2 (aq) + 16H+ (aq) + 10 Br" (aq) 2 Mn² + (aq) + 8 H2O(1) + 5 Br (1) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. 0-0 . 0 Write a balanced equation for the half-reaction that takes place at the cathode. x ? Write a balanced equation for the half-reaction that...
The redox reaction between hydrogen peroxide, H2O2, and permanganate ions, MnO4-, in acid solution are as...

The redox reaction between hydrogen peroxide, H2O2, and permanganate ions, MnO4-, in acid solution are as follows: 5H2O2(aq) + 2MnO4-(aq) + 6H+(aq) → 5O2(g) + 2Mn2+(aq) + 8H2O (l) 5 mol of MnO4-was required to reach the equilibrium. How many moles of H2O2were required to reach the equilibrium? a) 2 mol b. 10 mol c) 12.5 mol d) 25 mol

MnO4 (aq) + H2 C2O4(aq)Mn2+(aq) + CO2(g) 2. What element is being reduced in the following redox reaction? MnO4 (...

MnO4 (aq) + H2 C2O4(aq)Mn2+(aq) + CO2(g) 2. What element is being reduced in the following redox reaction? MnO4 (aq) + H2C2O4(aq) Mn2+(aq) + CO2(g)