Question

Write a python code that takes in an number 0-9 and prints out the word of the number. For example 1 would print out one. Below is the skeleton of the code that needs to be filled in.

def num2string(num):
	"""
	Takes as input a number, num, and
	returns the corresponding name as a string.
	Examples: num2string(0) returns "zero", num2string(1)returns "one"
	Assumes that input is an integer ranging from 0 to 9
	"""
	numString = ""
	###################################
	### FILL IN YOUR CODE HERE ###
	### Other than your name above, ###
	### this is the only section ###
	### you change in this program. ###
	###################################
	return(numString)
	def main():
	nums = input('Enter a multi-digit number: ')
	newStr = ""
	for n in nums:
	word = num2string(int(n))
	newStr = newStr + " " + word
	msg = 'In words, your number is:' + newStr + "."
	print(msg)
	#Allow script to be run directly:
	if __name__ == "__main__":
	main()

Answer 1

def num2string(num):
    """
    Takes as input a number, num, and
    returns the corresponding name as a string.
    Examples: num2string(0) returns "zero", num2string(1)returns "one"
    Assumes that input is an integer ranging from 0 to 9
    """
    numString = ""
    numbers = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    numString = numbers[num]
    return numString


def main():
    nums = input('Enter a multi-digit number: ')
    newStr = ""
    for n in nums:
        word = num2string(int(n))
        newStr = newStr + " " + word
    msg = 'In words, your number is:' + newStr + "."
    print(msg)


# Allow script to be run directly:
if __name__ == "__main__":
    main()

Enter a multi-digit number: In words, your number is:three eight five. Process finished with exit code 0